On Sun, Oct 12, 2003 at 02:49:53PM +0000, Curt Zirzow wrote:
: * Thus wrote Eugene Lee ([EMAIL PROTECTED]):
: > On Sun, Oct 12, 2003 at 02:09:38AM +0200, DvDmanDT wrote:
: > :
: > : Does anyone have a good solution on how to get the age of someone from a
: > : date column in mysql... This is what I have, but it's not really the
: > : truth... What's the right way to do it?
: > :
: > : floor((time()-$a["born"])/(3600*24*365.25))
: > :
: > : where $a["born"] is the timestamp of the birthdate... Current query:
: >
: > This should work for well-formed timestamps, i.e. they are not in the
: > future:
: >
: > function age($ts)
: > {
: > list($y1, $m1, $d1) = explode(' ', date('Y m d', $ts));
: > list($y2, $m2, $d2) = explode(' ', date('Y m d', time()));
: > $age = $y2 - $y1 - ((($m2 < $m1) || ($d2 < $d1)) ? 1 : 0);
:
: What happens if the month is the same but the day hasnt been
: reached?
:
: Shouldnt this be:
: $age = $y2 - $y1 - ((($m2 < $m1) || ($m2 == $m1 && $d2 < $d1)) ? 1 : 0);
:
: To account for it being the same month but not yet the day.
You're right. I got lost trying to short-circuit the expression and
forgot to explicitly test for same month. :-)
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