Hi,
Tuesday, October 21, 2003, 5:04:14 PM, you wrote:
JW> I am trying to create a remote status page for my website. So far, I
JW> have found the fsockopen() function and used the example code to create
JW> the following basic script:
JW> <?php
JW> $fp = fsockopen ("xxx.xxx.xxx.xxx", 80, $errno, $errstr, 30);
JW> if (!$fp) {
JW> echo "Down\n";
JW> }
JW> else {
JW> echo "Up\n";
JW> fclose ($fp);
JW> }
?>>
JW> While this works when the server is UP, I get the following error when
JW> it is down along with the 'Down' output:
JW> Warning: fsockopen(): php_hostconnect: connect failed in
JW> /****/public_html/status/test.php on line 2
JW> Warning: fsockopen(): unable to connect to xxx.xxx.xxx.xxx:80 in
JW> /****/public_html/status/test.php on line 2
JW> Down
JW> Can anyone help me out here?
JW> Thanks,
JW> Jason Williard
change your call to @fsockopen() which will tell it to ignore errors
--
regards,
Tom
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php