My fault! You are right, but thats not what I want. $value comes from a form filled by a user. I want $value to be an integer. Not a float. So if the user types "12.3" the system has to send an error msg.
Therefore the procedure.
By-the-way, Im using PHP 4.3.3 (on windows XP profesional. Don't say a thing!!! I rather work on my mac!) =)
Cesar
Curt Zirzow wrote:
* Thus wrote Cesar Cordovez ([EMAIL PROTECTED]):
Can somebody explain me why is this happening?
$value = "12.3"; $number = intval($value);
echo "Number: $number, Value: $value<br>"; // echoes: Number: 12, Value: 12.3
I'm guessing you wondering why the .3 is removed. Thats because 12.3 isn't an integer but a float.
$number = floatval($value);
if ($number != $value) { echo "Bad"; } else { echo "Good"; // echoes Good!!!!!! }
The previous should be echoing "Bad". (I think!)
correct. If you use the floatval() it will echo "Good".
Curt
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
