> > PHP Gurus, > If you say so... A few people have remarked about this. It's just a habit of mine. Whatever list I'm on, I address it to the "gurus" of that list. A guru being anyone who knows more than me, which is almost everyone. So on the CSS list, I address it to "CSS Gurus". On the GoLive list, it's to "GoLive Gurus". That's all. > Try: > echo "The results of the array are - " . $workshops[0][0] . " and " . > $workshops[1][0];
I'm not sure if I did something wrong, but when I tried this, the results came back like this: The results of the array are - 2 and 2 I have no idea what the twos are referring to. > while($r = mysql_fetch_row($result)) > { $workshop[] = $r[0]; } This works perfectly! And, more importantly, I learned what it is that you are doing here. Taking the one column of the array returned from the mysql_fetch_row() command and putting it into a slightly simpler array. And for this purpose a while() loop is less code than a for() loop. Elegant. That's solved the problem. Thank you. > Have you tried mysql_fetch_array()? Just thought I should mention this to Jay. Yes, I had been alternating my experiments with mysql_fetch_array() and mysql_fetch_row(), but the results, were exactly the same (or close enough that I don't remember otherwise). So I suspected that the problem lay elsewhere and didn't mention it. But thank you for suggesting alternatives. -- Cheers! Dave G [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php