--- Burak Delice <[EMAIL PROTECTED]> wrote: > http://localhost/menu.php?status=0 php return
[snip]
> if ($status==0) echo '"trying";
if (!$_GET['status'])
{
echo '"trying";
}
Hope that helps.
Chris
=====
Chris Shiflett - http://shiflett.org/
PHP Security Handbook
Coming mid-2004
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http://httphandbook.org/
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http://www.nyphp.org/ramp
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