From: "David Otton" <[EMAIL PROTECTED]>
> >From: "Ian Truelsen" <[EMAIL PROTECTED]>
> >
> >> What I want to do is to call a function from within a function, but
pass
> >> the secondary function name through the first function. Like this:
> >>
> >> function1(function2)
> >>
> >> Then call function2 from within function1. Unfortunately, I have been
> >> unable to figure out the proper syntax for calling the second function.
> >
> >$function = 'print';
> >$function('you mean like this??');
>
> Does that snippet run for you, as-is?
Of course not... lol...sorry...
But this does:
<?php
function myfunction($data)
{ echo $data; }
$function = 'myfunction';
$function('you mean like this??');
?>
$function must be a user defined function, I guess.
Same as with your example, you could just use $f(); instead of
call_user_func ($f);
Just depends which is clearer to you...
---John Holmes...
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