try this: $ar = array(); while ($row = mysql_fetch_assoc($sql)) { $ar[] = $row; }
olinux --- Jas <[EMAIL PROTECTED]> wrote: > I think I am loosing my mind this afternoon... could > someone review this > snippit and tell me why it isn't working? > > $sql = mysql_query("SELECT $i FROM $table WHERE $i = > $i",$db)or > die(mysql_error()); > while($b = mysql_fetch_array($sql)) { > while($ar = current($b) != 0) { > $v = array(); > list($v) = explode("}",$ar); } > print_r($v); } > > I am hoping to get something like > array([0]=>first row of data[1]=>second row of data) > > Any help would be great... > Jas > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > __________________________________ Do you Yahoo!? New Yahoo! Photos - easier uploading and sharing. http://photos.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php