Hello
I think there is some problem with the permission.
Even if I execute a command like -
echo ( "start" );
exec ( "pwd" );
echo ( "end" );
the output is - startend
shouldnt be pwd showing the present working directory
to me.
Karam
--- Jason Wong <[EMAIL PROTECTED]> wrote:
> On Saturday 06 December 2003 12:56, Karam Chand
> wrote:
>
> > looking at manuals and help and some help from
> you. i
> > wrote the attached code-
> >
> > error_reporting (E_ALL);
> > ini_set('display_errors', 1);
> >
> > $result = `./myapp`;
> > print_r ( $result );
> >
> > echo ( "2" );
> >
> > exec("./myapp",$result);
> > print_r($result);
> >
> > It is returning output
> >
> > 2Array ( )
> >
> > which means the array is empty !!!
> >
> > it should have outputted ErrorError
>
> I believe you mean to say that it should output:
> 2Error
>
> OK, does your "myapp" program dump its output to
> STDOUT?, Remember exec() only
> captures STDOUT.
>
> > Both the php and the binary exsits in
> > http://www.mydomain.com/mgmt/
>
> One way to satisfy yourself that exec() is working
> is to create a small test
> program, eg:
>
> ----8<-------------
> #!/bin/bash
> echo "test"
> ----8<-------------
>
> Then exec() it.
>
> > Can I send you the binary so that you can check it
> > out?
>
> No thank you.
>
> --
> Jason Wong -> Gremlins Associates ->
> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet
> Applications Development *
> ------------------------------------------
> Search the list archives before you post
> http://marc.theaimsgroup.com/?l=php-general
> ------------------------------------------
> /*
> The girl who stoops to conquer usually wears a
> low-cut dress.
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>
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