Dear Friends

These is my sample code

test1.html

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME="Generator" CONTENT="EditPlus">
<META NAME="Author" CONTENT="">
<META NAME="Keywords" CONTENT="">
<META NAME="Description" CONTENT="">
</HEAD>

<BODY>

<form name="frm1" method="POST" action="test1.php3"
enctype="multipart/form-data">
<input type="text" name=text1 value="">
<input type=file name=file1>
<input type=submit name=btnsubmit value="Submit">
</form>

</BODY>
</HTML>


test1.php3

<html>
<head><title>Test Page</title></head>
<body>

<form>

<?
echo $text1;
echo $file1;
echo $file1_name;
copy($file1,"d:\prashant\$file1");
?>

</form>
</body>
</html>

I am Facing the problem that if i use enctype="multipart/form-data" in form
object
then i am unable to retrieve the values passed from .html form.

So if i am using a File Upload control in my form without the enctype
attribute,then i get a warning message

Unable to open '' for reading: No such file or directory in
/home/httpd/html/fai/test1.php3 on line 12

i.e My HTML Form with Post Method and enctype
attribute="multipart/form-data" is not working for passing data to the web
server.

The problem can be solved without the enctype attribute in the Form Tag
where i can send the Data to the
Web Server and the values getting retrieved in another Php Page, but what
about if i have to upload
a File using the File Upload control <input type=file name=file1> in my HTML
Form.

It Fails in this case where i get the warning message.

Can somebody help me in this regard as soon as possible ???

Thanks,
Prashant S Akerkar



----- Original Message -----
From: "Jason Wong" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, November 08, 2003 3:37 PM
Subject: Re: [PHP] fopen url


> On Saturday 08 November 2003 08:21, John Hagstrand wrote:
>
> > Thanks for your snot.
>
> They were surplus to requirements so you're welcome to them.
>
> >  The code you wrote below,
> >
> > >   echo fopen("http://www.google.com";, 'r');
> > >   echo fopen("http://news.google.com";, 'r');
> >
> > I've implmented at this url.
> > http://www.globalscoop.com/gs/feeds/testUrl.php
> >
> > You can see the error I'm getting.  Would you take a look?
>
> No. Would you mind posting the error you're getting so that everyone can
see?
> And please confirm that whatever error you're getting is in response to
the
> exact code as above.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
> ------------------------------------------
> Search the list archives before you post
> http://marc.theaimsgroup.com/?l=php-general
> ------------------------------------------
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>
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>

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