That isn't the problem since the header() should be called way before any output... this is something bizarre here... The offending code is a block right smack in the middle of a bunch of other html stuff - which is totally similar and removing these lines of code fixes it. So strange. AND it is not just one of the rows or something - it is that block as a unit for some reason.
On Dec 10, 2003, at 11:53 PM, TheHeadSage wrote:
Is the HTML code before or after the header? As the header(); function should be before any output is passed to the browser.
I advise you read about the header() function in the PHP manual.
----- Original Message ----- From: "rogue" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Thursday, December 11, 2003 2:34 PM Subject: [PHP] Error that I can't find causing header() to fail
Hi all,
This template I have, has been driving me nuts. I am trying to debug someone else's code and have narrowed the problem down to a few lines, but I can't see what would be causing the problem.
Here is the scoop. When this template loads it is making:
header("Location: http://www.myurl.com")
Fail. If I remove the following hunk of code, everything works as it should on the template (redirecting me to the right place). Removing any ONE row or combination does not seem to fix it, so there is something to do with this whole block? I am at a loss here and could really use another pair of eyes.
<snip>
<tr> <td nowrap align="right"> <b>Fax:</b> </td> <td> <input name="fax" type="text" size="35" maxlength="20" value="<?php echo $fax; ?>"> </td> </tr> <tr> <td nowrap align="right"> <b>Street:</b> </td> <td> <input name="street1" type="text" size="35" maxlength="100" value="<?php echo $street1; ?>"> </td> </tr> <tr> <td nowrap align="right">
</td> <td> <input name="street2" type="text" size="35" maxlength="100" value="<?php echo $street2; ?>"> </td> </tr> <tr> <td nowrap align="right"> <b>City:</b> </td> <td> <input name="city" type="text" maxlength="20" value="<?php echo $city; ?>"> State: <select name="state"> <?php mysql_select_db("main_db",$db) or die ("Unable to select database"); $sql = "SELECT * FROM states WHERE display='yes' ORDER BY state"; $result = mysql_query($sql,$db) or die ("Error in query: $sql". mysql_error()); while($stateNow = mysql_fetch_array($result)) { $state_name = $stateNow[state];
print "<option value='$state_name'"; if ($state_name == $state) { print " SELECTED "; } elseif ($state_name == "NJ") { print " SELECTED "; } print ">$state_name</option>\n"; } ?> </select> </td> </tr>
</snip>
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