Your first query, could it be that you dont have any reference between the
two tables?

You should have a link between them, like

where t1.id=t2id

Or else you do not have any reasonable way of predicting the outcome of the
query. Atleast this is what I know from my own experience.

Especially if t2 has more entries for each entry in t1, your query will
result
in unpredictable manner.

Hope this helps.

-- 
Kim Steinhaug
---------------------------------------------------------------
There are 10 types of people when it comes to binary numbers:
those who understand them, and those who don't.
---------------------------------------------------------------


"Patrik Fomin" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
>
> q1)
> i got a database with 2 diffrent tables,
> i want to take out all the information that arent duplicated from
> on of the tables, like this:
>
> $sql = "SELECT t1.rubrik, t1.info, t2.priser FROM table1 AS t1, table2 AS
t2
> WHERE t1.arkiv = '0' ORDER BY t1.rubrik";
>
> the problem is that i got alot of duplicates (its for another purpose), so
i
> need to filter out the duplicates in the rubrik field to get just one
match
> each, like:
>
> id - rubrik - info
>
> 0 - aaaa - some info
> 1 - bbbb - some info
> 2 - cccc - some info
> 3 - aaaa - some info
> 4 - dddd - some info
>
> would print out
> 0 - aaaa - some info
> 1 - bbbb - some info
> 2 - cccc - some info
> 3 - dddd - some info
>
>
> q2)
> i got like 100 matches from a database into a $num variable,
> then i want to devide that by 3 aslong as it can be done, eg:
>
> while ($num != 0) {
>
> ïf ($num / 3 = true){
> some code to display some fields from a database
>
> $num = $num - 3;
> }
> else {
> some other code to display
> $num = 0;
> }
> }
>
> basicly i want the if statement to check if its more then 3 posts left to
> print out, if not its gonna print out the remaining last 1 - 2 post in a
> diffrent way (for the looks)
>
>
> regards
> patrick

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