Try SELECT teams.*, divisions.id AS divisonid, divisions.name AS divisionname FROM teams LEFT JOIN divisions ON teams.divisonID = divisions.divisionID
if the ids are the same you can actually also write ON teams.divisonID and omit = divisions.divisionID ... I think. hth toby > I'm looking for a good way to do the following: > > I have two tables, one named teams and one named divisions. > Divisions relates divisionID to the name of the division > (division_name). In teams I have the divisionID stored > along with the team_name. [BG info: teams can be relegated > or promoted so it's easier for me to store the divID in > the teams table] I'd like to populate a drop down menu with > the team_name and division_name and was wondering if I can > do some kind of select statement that will get all the info > at once with the following details on the two tables: > > mysql> select * from teams; > +--------+-----------+---------+------------+------+------------+-----+----- -+-----+-----------+---------------+ > | teamID | team_name | coachID | divisionID | paid | pmnt_notes | win | loss | tie | goals_for | goals_against | > +--------+-----------+---------+------------+------+------------+-----+----- -+-----+-----------+---------------+ > | 1 | Metro | 0 | 1 | n | NULL | 0 | 0 | 0 | 0 | 0 | > +--------+-----------+---------+------------+------+------------+-----+----- -+-----+-----------+---------------+ > 1 row in set (0.00 sec) > > mysql> select * from divisions; > +------------+------------------+ > | divisionID | division_name | > +------------+------------------+ > | 1 | Premier | > | 2 | Classic | > | 3 | Recreational 7v7 | > +------------+------------------+ > 3 rows in set (0.00 sec) > > Thanks in advance! > Kirk > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
