On Mon, Jan 19, 2004 at 06:50:37PM +0200, John Clegg wrote:
> Hi
>
> I am having some problems with preg_replace and I wondering if someone
> could suggest a fix or explain why it is not working.
>
>
>
> Here is the Code:
> *********************
> <?php
> $code = "blah http://www.foo.com/Unsubscribe.php?EmailAddress=[MAIL] blah";
> $url = "'http://www.foo.com/maxbid/Unsubscribe.php?EmailAddress=[MAIL]'";
> echo "BEFORE : $code<br><br>";
> $replace = "Foo";
> $code = preg_replace($url,$replace,$code,1);
> echo "AFTER: $code<br>";
> ?>
> **********************
>
> Here is the results of the script:
>
> **********************
> BEFORE : blah
> http://www.qxlmaxbid.com/maxbid/Unsubscribe.php?EmailAddress=[MAIL] blah
>
> AFTER: blah
> http://www.qxlmaxbid.com/maxbid/Unsubscribe.php?EmailAddress=[MAIL] blah
>
> **********************
>
> It should give the following result:
>
> **********************
>
> AFTER: blah Foo blah
>
> **********************
preg_replace expects the first argument to be a pattern, which should be
enclosed in forward slashes ("//"). So your $url variable should be
surrounded with slashes. You have single quotes in your $url variable,
but I don't think that PHP behaves like perl in letting you use
whichever delimiter you choose. Try replacing the single quotes with
forward slashes.
Additionally, if you're only doing a simple string substitution, you
should use str_replace instead:
http://php.net/str_replace
You won't need the "/" delimiters, and it will be faster than using
preg_replace.
joel
--
[ joel boonstra | gospelcom.net ]
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