You can replace {0,1} with a question mark and [0-9] with \d (digit). Also, and I$string = 'ab12345-1'; if (preg_match('/^([a-zåäö]{2,3})([0-9]{4,5}(\-[0-9]{1,2}){0,1})$/i', $string, $m='')) { echo $m[1]; // -> ab echo $m[2]; // -> 12345-1 }
g. martin luethi
think this is not in the PHP documentation, you can use POSIX character classes
inside the brackets. If you want to match alphabetical characters including
the Swedish and various other international ones like æ or ü, you can use [:alpha:].
You may not need it in this example, but it's excellent for internationalized regex matching.
if (preg_match('/^([[:alpha:]]{2,3})(\d{4,5}(\-\d{1,2})?)$/i',
Tue, 20 Jan 2004 09:59:37 +0100 Victor Spång Arthursson <[EMAIL PROTECTED]>:
Hi!
Anyone who could help me with this regexp problem?
I want to verify that a string is made up of 2-3 letters, (a-z + åäö, A-Z + ÅÖÄ), directly followed by 4 or 5 digits, which could, but may not, be followed by a minus and one or two digits.
Examples of valid strings:
abc12345 ABC12345 abc1234 ABC12345-1 ABC12345-01
I would also like to split them into an array consisting of 2 elements;
[0] = the first 2 or 3 letters [1] = the rest
Example:
string = ab12345 [0] = ab [1] = 12345
string = åäö1234-66 [0] = åäö [1] = 1234-66
Lots of thanks in advance,
sincerely
Victor -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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