On 27 January 2004 05:50, Paul Furman wrote:
> Shawn McKenzie wrote:
> > I've noticed in both of your posts that you aren't terminating the
> > line before the include with a ;
>
> Yup, thanks!
>
> Then I fixed my global problem without bugging you guys too.
Actually, no you didn't -- you just bypassed it.
> Final result:
>
>
> #call.php
> $dirstr= "./";
> include 'scandir.php';
> scandir('$dirstr');
Becasue single-quoted strings don't do variable interpolation, you are
actually passing the literal string '$dirstr' to the function -- no the
*value* of $dirstr, which is what you want. If you needed to use quotes
here, they should be double ones -- but, actually, you don't need quotes at
all: since what you really you want is the value of $dirstr, this will do
the trick:
scandir($dirstr);
> #scandir.php
> function scandir($dirstr) {
Well, now this $dirstr will be set to '$dirstr', which clearly isn't a valid
directory path!
> global $dirstr; #I HAD TO ADD THIS LINE ALSO
But you've now bypassed that by equivalencing it to the global version of
$dirstr, which, of course, still contains './', so the rest of the function
works. Once you take the quotes off the function call above, you also won't
need this global statement.
> $files = array();
> $fh = opendir($dirstr);
> while (false !== ($filename = readdir($fh))) {
> array_push($files, $filename);
> }
> closedir($fh);
> return $files;
> }
>
> > FYI...
> > If you use / then you don't have to escape it like // only the \.
> > Also, instead of ".\\" you can use '.\'
Actually, no you can't, because in single quoted strings \' is the sequence
to insert a single quote! So you still ahve ti use '.\\'.
Cheers!
Mike
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