So what is the problem?
----- Original Message -----
From: Radwan Aladdin
To: [EMAIL PROTECTED]
Sent: Thursday, January 29, 2004 10:40 AM
Subject: The final script! but still some problems..
Hi all..
This is the final PHP code that I written.. but there i some problems.. not errors..
I said problems.. For example the Distance value is not updated correctly.. and the
LessonNumber field also.. please help me fixing these problems :
<?php
include("Config.php");
$link = mysql_connect("$user_hostname", "$user_username", "$user_password");
mysql_select_db("$user_database", $link);
$UserName = $_GET['UserName'];
$Password = $_GET['Password'];
$LogoutTime = date("U");
$query1 = "UPDATE accounts SET LogoutTime=$LogoutTime";
$result1 = mysql_query($query1) or die("Query error: " . mysql_error());
$query2 = "SELECT LoginTime,Distance,LessonNumber FROM accounts WHERE
`UserName`='$UserName' AND
`Password`='$Password'";
$result2 = mysql_query($query2) or die("Query error: " . mysql_error());
$row2 = mysql_fetch_row($result2);
$query3 = "UPDATE accounts SET LessonNumber=LessonNumber + 1";
$RightLoginTime = $row2["LoginTime"];
$Distance = $row2["Distance"];
$LessonNumber = $row2["LessonNumber"];
$LessonsTimeLimit = "30";
?> <pre> <?
echo $query1;
echo $query2;
echo $query3;
?> </pre> <?
$query4 = "UPDATE accounts SET Distance=" . ($LogoutTime - $RightLoginTime) . "
WHERE
UserName='$UserName' AND Password='$Password'";
$result4 = mysql_query($query4) or die("Query error: " . mysql_error());));
$query5 = "SELECT Distance FROM accounts";
$result5 = mysql_query($query5) or die("Query error: " . mysql_error());
$row3 = mysql_fetch_row($result5);
$UpdatedDistance = $row3["Distance"];
?> <pre> <?
echo $query4;
?> </pre> <?
if($Distance == $LessonsTimeLimit){
$result3 = mysql_query($query3) or die("Query error: " . mysql_error());
}else{
echo "Not yet!";
}
?>
I'm sure it is very easy for you.. I hope that..
Regards..