1. Using [] creates a new array element. Hence the error. You can try this
piece of code inside the loop
[code]
if (strstr ($file, '.jpg')){
$refPictures = & $pictures[];
$refPictures = $file;
print $refPictures;
}
[/code]
$refPictures holds a reference to the newly created element of the $pictures
array. Therefore, by assigning $file to $refPictures, $file is actually
getting assigned to the newly created element of the $pictures array. The
same logic applies in the print statement
2. Again, using [] in the var_dump indicates that you are trying to create a
new element of the $pictures array. If dumping the contents of the entire
array along with their data types and such is what you are trying to
achieve, the correct syntax is
[code]
var_dump($pictures);
[/code]
> -----Original Message-----
> From: Paul Furman [mailto:[EMAIL PROTECTED]
> Sent: Friday, February 06, 2004 3:09 PM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] beginner question about while loops
>
>
> Eric Gorr wrote:
> >
> >> the while function knows to just go through those and fills in array
> >> numbers accordingly?
> >
> >
> > The while function has nothing to do with it. Using the syntax $array[]
> > simply adds an element onto the _end_ of the array and PHP picks the
> > next logical, numerical index.
>
>
> OK thanks guys, I got the missing curly brace & some other messes.
>
> So when assigning values to an array inside a loop, it knows to advance
> to the next but then if I want to print those out at the same time, it's
> complaining
>
> while ($file = readdir($fh)){
> if (strstr ($file, '.jpg')){
> $pictures[] = $file;
> #print $pictures[]; #Fatal error: Cannot use [] for reading
> }
> var_dump ($pictures[]); #Fatal error: Cannot use [] for reading
> }
>
>
>
> This one works but complains about Undefined variable: pictures NULL
> array (but it dumps the contents of $pictures[]:
>
> while ($file = readdir($fh)){
> if (strstr ($file, '.jpg')){
> $pictures[] = $file;
> }
> var_dump ($pictures);
> }
>
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