Hello John,
> From: JohnT [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, February 10, 2004 4:54 AM
>
> Hello,
>
> mind explain a little bit further cause i'm confused and not
> sure if the
> fuction really work or something
>
> [some Code]
As far as I know (or understand), unset() will only destroy the reference to a
variable.
That's why you get sometimes a bit confusing results when unset variables insinde
functions, because they are often just a reference or even a copy of another variable.
(for example using global $a; is equal to $a =& $GLOBALS['a'])
See:
Chapter References Explained
-> Unsetting References
and Function Reference of unset()
of the php Manual.
Now I guess that a static variable is only available via reference in a function call.
Otherwise it would be unseted if the function call is finished, what's not the use of
a static var.
How to fix this problem:
The purpose of your code was to reset the value of the static variable.
So just do this reseting by assigning the value you wanted, e.g.
/////////////// CODE /////////////////
function foo() {
static $a;
$a++;
echo "$a<BR>";
$a = 0;
}
foo();
foo();
foo();
///////////////////////////////////////////////
Now it outputs:
1
1
1
Regards,
Dirk Oschlies
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