From: "John Taylor-Johnston" <[EMAIL PROTECTED]>
> I want to create a language option, so the resulting html is in French or
English, depending. But passing variables like this doesn't work:
>
> <?php include ("../_phpcode/byname.php?lang=fr"); ?>
>
> echo $lang; // 'fr'
>
> Warning: main(): Failed opening '../_phpcode/byname.php?lang=fr'
> for inclusion (include_path='.:/usr/local/share/pear')
in
> /home/users/q/qx04t9mu/www/.../parnoms.htm on line 125
>
> It will work if I use a URL.
>
> <?php include ("http://foo.com/_phpcode/byname.php?lang=fr";); ?>
>
> echo $lang; // 'fr'
>
> Ideas on how to pass a variable?
include() code runs in the same scope as where you call include(). So you
can do this.
$lang = 'fr';
include('../_phpcode/byname.php');
and $lang will be available within the include file.
---John Holmes...
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