On 17 March 2004 17:09, Chris W. Parker wrote:
>
> $var++ is a post incrementer meaning the value is updated at the next
> command*.
> * i'm not exactly sure how the compiler determines when to post
> increment, but i think i'm correct.
Not quite -- the increment is performed immediately after the access -- in
fact, as part of the same operation. So:
$x = 3;
$y = ($x++ * 2) + $x;
is likely to give you $y==10, not 9.
(I say "is likely to", because you don't have any absolute cast-iron
guarantees that a compiler won't, if it thinks it has good reason, commute
the above to $x + ($x++ * 2), which would give you $y==9! In general, it's
best to regard the value of a pre- or post-incremented variable as uncertain
in the rest of the expression containing it.)
Cheers!
Mike
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