$id = preg_replace("/^0+(.*)$/","//1",$id);
instead
Monty wrote:
I tried removing the zeros, but, I get the same result:
$id = 000011; $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ???
This didn't work either:
$id = 000011; settype($id, 'string'); $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ???
No matter what I do, $id=000011 is seen as "9". Only way is to pass the number without the zeros ($id=11), but, because this data is being read from a database, I can't change the format because PHP seems to be converting it immediately to a 9 instead of reading it as 11 or even 000011.
If PHP sees this as an octal, then why does gettype(000011) = INTEGER? This makes no sense.
Monty.
From: [EMAIL PROTECTED] (Jay Blanchard) Newsgroups: php.general Date: Fri, 2 Apr 2004 15:38:03 -0600 To: "Monty" <[EMAIL PROTECTED]>, <[EMAIL PROTECTED]> Subject: RE: [PHP] Strange Numeric Conversion...
[snip] Why is this happening???
$id = 000011; echo $id; // Displays: 9
$id = 11; echo $id; // Displays: 11
How do I make the first number (00011) display as 11? Why is it showing 9? [/snip]
First of all you have "naked" numbers. The first one, 000011, looks like a binary number (which actually should be 3). You are going to have to trim the leading zero's from the number to have it display as 11.
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