I thought about doing it this way, but repeating this 50 times seems a bit
ineffecient, perhaps i am looking for a shortcut that does not exist? I had
hoped I was missing something obivious.
Thanks
Steve
----- Original Message -----
From: "Peter Houchin" <[EMAIL PROTECTED]>
To: "S. Efurd" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, March 27, 2001 7:08 PM
Subject: RE: [PHP] setting Check box
> use
> <SELECT NAME="foo"> <OPTION VALUE="bar" <? if ($areacode == 'bar') { echo
'SELECTED '; }?>>foo bar</OPTION>
>
> Peter
> Ps thanks again David & Jason M & Phillip for your help :>
> -----Original Message-----
> From: S. Efurd [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, March 28, 2001 10:48 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] setting Check box
>
>
> This worked for me as well, and helped me with a problem I was having!
>
> How would you show what option was selected in a drop down box. I have a
> form the user fills out, this goes to a confirmation page to ensure the
data
> enetered is correct. I have a drop down box for states, and I cant seem to
> make it show the state selected it always defaults to first choice?
>
> Thanks
>
>
>
>
> ----- Original Message -----
> From: "David Robley" <[EMAIL PROTECTED]>
> To: "Peter Houchin" <[EMAIL PROTECTED]>; "Php-General@Lists. Php. Net"
> <[EMAIL PROTECTED]>
> Sent: Monday, March 26, 2001 11:37 PM
> Subject: Re: [PHP] setting Check box
>
>
> > On Tue, 27 Mar 2001 14:24, Peter Houchin wrote:
> > > >> Hiya can some one pls let me know if i am on the right track pls,
> > > >> this is in a form that updates if there is an id else it inserts,
> > > >> now what i want it if there is an id i want the check box to be
> > > >> either checked or unchecked depending on the 'y' / 'n' value in the
> > > >> db
> > >
> > >
> > >
> > > >> <input type="checkbox" name="avail" value="" <? if ($avail == 'n')
> > > >> { echo 'SELECTED '; }?>">
> > >
> > >
> > >
> > > >> Peter Houchin
> > >
> > >
> > >
> > > > Try CHECKED for checkboxes - SELECTED works for dropdowns.
> > >
> > >
> > > ok I've changed it the SELECT to CHECKED but it had no effect ...
> > > <input type="checkbox" name="avail" value="" <? if ($avail == 'n') {
> > > echo 'CHECKED'; }?>>
> > > I've also tried it with a "n" value so it reads like
> > > <input type="checkbox" name="avail" value="n" <? if ($avail == 'n') {
> > > echo 'CHECKED'; }?>> but that didn't have any luck either ... is there
> > > anything else i can do?
> > > Peter
> >
> > Well, this little snippet works for me...
> >
> > <?php
> > $avail = 'n';
> > ?>
> >
> > <FORM ACTION=check.php METHOD=GET>
> > <input type="checkbox" name="avail" value="" <?php if ($avail == 'n')
>
> > echo 'CHECKED'; }?>>
> > <INPUT TYPE=SUBMIT>
> > </FORM>
> >
> > <?php
> > if(isset($avail)) {
> > echo "Value of AVAIL: $avail";
> > }
> > ?>
> >
> > If you aren't getting the value you expect in $avail you may have
> > problems.
> >
> > --
> > David Robley | WEBMASTER & Mail List Admin
> > RESEARCH CENTRE FOR INJURY STUDIES | http://www.nisu.flinders.edu.au/
> > AusEinet | http://auseinet.flinders.edu.au/
> > Flinders University, ADELAIDE, SOUTH AUSTRALIA
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
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> > For additional commands, e-mail: [EMAIL PROTECTED]
> > To contact the list administrators, e-mail: [EMAIL PROTECTED]
> >
> >
>
>
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