[snip]
ok, this same query, works EVERYWHERE ELSE, why won't it work now? it
returns to me:
Warning: Supplied argument is not a valid MySQL result resource
$query_result = mysql_query("SELECT * FROM AotH_Users");
while ($row = mysql_fetch_array($query_result, MYSQL_NUM)){
[/snip]
When are you guys going to learn about error reporting, huh? Try this
(verbose)
$query = "SELECT * FROM AotH_Users";
if(!($result = mysql_query($query, connection_string))){
echo mysql_error();
exit();
}
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php