[snip]
$phone = '1234567890';
$newphone = preg_replace('/(\d{3})(\d{3})(\d)/','(\1)\2-\3',$phone);
echo $newphone.'<br>';
--
regards,
Tom
[/snip]
ok sorry but since i never used preg_* before i dont quite get what some of
this stuff means. i looked at the doc page for it but it doesnt make mention
at all of what \d, \w, \s or any of those things mean... i only assume that
\d means digit and \w or \s means blank space??
anyways to go through the whole example above part by part:
$phone = '1234567890';//understand that
$newphone = preg_replace(//ok now what does this stuff
//mean??
'/(\d{3})(\d{3})(\d)/'
im gathering the line above is the search string (what to look for)? if so i
get from it that it is supposed to look for the first block of 3 digits then
the second block of 3 digits and the other 4 numbers by themself in a sense
seperating the string into 3 different parts: 123 456 7890 and then asigning
like "id numbers to the blocks"
'(\1)\2-\3'
and this one above says put block 1 between (). take block 2 and put a -
after it and leave the other 4 numbers alone to come up with: (123)456-7890
$phone);
the original number to do the replace on of course
let me know if i got that set right
--
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