I am trying to design a custom form script and I've stumbled across a small
problem.
I want to implement a file upload into the form, but rather than posting to
another file I want to refresh the form and then show that there has been a
file uploaded.
I know about changing the form action to:
<form action="<?php echo$_SERVER['PHP_SELF']; ?>" method="post" name="form"
id="form">
But, what do I need to change to update the script?
I'm a newbie, but trying hard to learn!
Thanks in advance for any help.
Tom
<form action="upload.php" method="post" ENCTYPE="multipart/form-data">
<input type="file" size="60" name="spec">
<!-- set the max file size -->
<input type="hidden" name="MAX_FILE_SIZE" value="500000">
<input type="submit" value="upload">
</form>
<?php
//FILE UPLOAD SCRIPT
$file = $_POST[file];
$path = "/relative/directory/to/file"; //SET THIS TO THE RELATIVE PATH FROM
WHERE THE SCRIPT IS TO WHERE THE FILE SHOULD BE UPLOADED TO,
if($file){
print("File name: $file_name<P>/n");
print("File size: $file_size bytes<P>/n");
if(copy($file, "$path/$filename")){
print("Your File was uploaded successfully");
}else{
print("ERROR, your file was not successfully uploaded");
}
unlink($file);
}
?>
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