Hi All, Can anyone tell me how to pass arguments to a PHP script from the command line? I know I need to use the -args option but how exactly, I have tried the following...
/usr/bin/php myscript.php -args key=value but this does not work, the script executes but key is not available as $_GET["key"] in my script. Any pointers will be much appreciated. TIA Phil. --- Phil Ewington - Technical Director 43 Plc - Ashdale House 35 Broad Street, Wokingham Berkshire RG40 1AU T: +44 (0)1189 789 500 F: +44 (0)1189 784 994 E: mailto:[EMAIL PROTECTED] W: www.soyouthink.com --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.701 / Virus Database: 458 - Release Date: 07/06/2004 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
