"Bob Lockie" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > I want to pass a function as a parameter and execute it in another function. > A callback. :-) > > For example: > > function a() { > echo "a"; > } > > > function b( $func ) { > func(); > echo "b"; > } > > > The output of "b( a )" will be "ab".
Take a look at call_user_func(): http://de3.php.net/manual/en/function.call-user-func.php You have to pass the name of the function instead of the function itself: function a() { echo "a"; } function b($func) { call_user_func($func); echo "b"; } b('a'); Regards, Torsten -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php