I suppose it was mysql_close that was a problem but I am not secure. I am
new in this.
I have tryed to made registration page. I wish to that you can use one nic
name ony one time.
I hav use the following code:
<body>
<?php include("header.inc");
if (isset($_POST['submit'])) { // Handle the form
require_once ("mysql_connect.php");
// Create a funtion for escaping the data.
function escape_data ($data) {
global $dbc; // Ned the conection
if (ini_get('magic_quotes_gpc')) {
$data = stripslashes($data);
}
return mysql_real_escape_string($data, $dbc);
} // End of function
$message = NULL; //Create an empty new variable
if (empty($_POST['name'])) {
$name = FALSE;
$message = '<p> You forgot to enter your name</p>';
} else {
$name = escape_data($_POST['name']);
if (empty($_POST['email'])) {
$email = FALSE;
$message = '<p> You forgot to enter your email</p>';
} else {
$email = escape_data($_POST['email']);
if (empty($_POST['username'])) {
$username = FALSE;
$message = '<p> You forgot to enter your username</p>';
} else {
$username = escape_data($_POST['username']);
if (empty($_POST['password1'])) {
$password1 = FALSE;
$message = '<p> You forgot to enter your password</p>';
} else {
if ($_POST['password1'] == $_POST['password2']) {
$password1 = escape_data($_POST['password1']);
} else {
$password = FALSE;
$message = '<p> your password did not math</p>';
}
}
if ($name && $email && $username && $password) // If everything's ok.
$query = "SELECT usrid FROM users WHERE username='$username'";
$result = @mysql_query ($query); //Run the query
if (mysql_num_rows($result) == 0) { // Make the query
$query = "INSERT INTO users (username, name, email, password,
registration_date) VALUES
('$username', '$name', '$email', '$password', NOW() )";
$result = @mysql_query ($query);
if ($result) { // IF it ran OK
// Send an email, if desired
echo '<p><b>You have been registered!</b></P>';
include("./footer.inc");
exit();
} else { // If it did not ron OK.
$message = '<p>You cout not be registered due to a system error. We
apologize for any inconvenience</p>';
}
} else {
$message = '<p>That username is alredy taken.</p>';
}
mysql_close();
} else {
$message = '<p>Please try again.</p>';
}
} // End of the main submit conditional.
// Print the error message if ther is one
if (isset($message)) {
echo '<font color="red">', $message, '</font>';
)
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<fieldset><legend>Enter your information in the form below:</legend>
<p><b>Name</b> <input type="text" name="name" size="15" maxlength="15"
value="<?php if (isset($_POST['name'])) echo $_POST['name']; ?>" /></p>
<p><b>Email Adress</b> <input type="text" name="email" size="40"
maxlength="40"
value="<?php if (isset($_POST['email'])) echo $_POST['email']; ?>" /></p>
<p><b>User Name</b> <input type="text" name="username" size="10"
maxlength="20"
value="<?php if (isset($_POST['username'])) echo $_POST['username']; ?>"
/></p>
<p><b>Password</b> <input type="password" name="password1" size="20"
maxlength="20" /></p>
<p><b>Confirm Password</b> <input type="password" name="password2"
size="20" maxlength="20" /></p>
<div align="center"><input type="submit" name="Submit" value="Register"
/></div>
</fieldset>
</form>
<?php
include("./footer.inc");
?>
</body>
</html>
but it dont work. If I take away al after mysql close to form_action it com
the folloving error:Parse error: parse error on line 114 (it is on the end
of the script). But when I set it back aganst the error massages coms on the
line of mysql_close. Are ther someone that understand what I means??
Thanks for any proposal
Erik Gjertsen
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