I see one problem, but not the one you are talking about.
> // Convert Values to Variables:
> $Title = $_POST[Title];
This (and the rest of the post fields) should have quotes:
$Title = $_POST["Title"];
(php looks for a constant named Title, instead of the string "Title")
What line gives you the parse error?
On Mon, 19 Jul 2004 11:10:09 +0100, Harlequin
<[EMAIL PROTECTED]> wrote:
> I've checked my syntax but obviously missing something.
>
> Would anyone mind a quick scan:
>
> // Convert Values to Variables:
> $Title = $_POST[Title];
> $ChristianName = $_POST[ChristianName];
> $MiddleName = $_POST[MiddleName];
> $Surname = $_POST[Surname];
> $HomePhone = $_POST[HomePhone];
> $Address01 = $_POST[Address01];
> $Address02 = $_POST[Address02];
> $Address03 = $_POST[Address03];
> $City = $_POST[City];
> $Postcode = $_POST[Postcode];
> $Country = $_POST[Country];
> $Nationality = $_POST[Nationality];
> $Gender = $_POST[Gender];
> $WorkPermitRequired = $_POST[WorkPermitRequired];
> $MyStatus = $_POST[MyStatus];
>
> // Dump Data Into MembersData:
> $UserDataDump = "INSERT INTO MembersData (Title, ChristianName,
> MiddleName, Surname, DOB, TelephoneHome, Address01, Address02, Address03,
> AddressCity, AddressPostcode, AddressCountry, Nationality, Gender,
> WorkPermit, Status)
>
> VALUES('$Title','$ChristianName','$MiddleName','$Surname','$HomePhone','$Add
> ress01','$Address02','$Address03','$City','$Postcode','$Country','$Nationali
> ty','$Gender','$WorkPermitRequired','$MyStatus')";
> mysql_query($UserDataDump) or die("Couldn't Create User Data Entry. MySQL
> Error: " . mysql_error());
>
> --
> -----------------------------
> Michael Mason
> Arras People
> www.arraspeople.co.uk
> -----------------------------
>
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>
>
--
Jim Root
[EMAIL PROTECTED]
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