On Sat, 2004-08-21 at 10:24, Curt Zirzow wrote:
> * Thus wrote Robert Cummings:
> > On Sat, 2004-08-21 at 00:10, Curt Zirzow wrote:
> > > * Thus wrote Robert Cummings:
> > > > Hi All,
> > > >
> > > > I think I'm looking for something that doesn't exist, but just in
> > > > case thought I'd check the list. Does anyone know if a PHP function
> > > > exists to get the number of references on a given variable's data? I was
> > > > hoping to create a way for a factory to automatically recycle resources
> > > > without the need for the developer to call some kind of free() method.
> > > > If I could get the internal reference count then I'd be able to
> > > > determine if it is free by virtue of only 1 reference (the factory).
> > > > This is for PHP4 btw, the solution is trivial in PHP5 using destructors.
> > >
> > > unfortantly there isn't a method to determain this.
> > >
> > > Be careful with PHP5, i'm not sure if its applicable in your
> > > situation, but there does seem to be rumor that php5 objects are
> > > assigned by reference, which isn't true:
> > >
> > > $o1 = new object();
> > > $o2 = $o1;
> > > unset($o2);
> > >
> > > the Object still exists, and the destructor isn't called.
> > >
> > > vs.
> > >
> > > $o3 = new object();
> > > $o4 =& $o3;
> > > unset($o3);
>
> Sorry, those unset's should be:
>
> $o2 = null;
> and
> $o3 = null;
>
> It's was to demonstrate that = and =& are *not* the same thing as
> one would believe since the term 'assigned by reference' is used.
As exemplified in the sample script I sent in my last response and by
the link sent by Hannes Magnusson, in PHP5 the following have identical
behaviour:
$o1 = new Foo();
$o2 = $o1;
// Is same as...
$o1 = new Foo();
$o2 =& $o1;
This was not true in PHP4 which is what a developer from PHP4 coming to
PHP5 needs to be aware of when using objects.
Cheers,
Rob.
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