* Thus wrote Neil:
>
>
> Not sure if its me or the configuration of PHP
variable variables are rather standard and dont have any
configuration settings.
>
> I have played around with this bit of code from operators part of the
> manual and this does not appear to work, well for me at least.
>
> $foo = "test";
> $$bar = "this is";
>
> echo "${$bar} $foo"; // prints "this is test"
Everything is working so far as expected
> Note: it is the same as
> echo "$test $foo"; // ***** for me it only prints out "test"
You are throwing me here.. the problem seems to be that $test
hasn't been assign. By using your examples I can make $test
actually be a value by doing this with the variable variable:
$$foo = 'avalue'; // $test is assinge 'avalue'
Is equivalent as doing:
$test = 'avalue'; // $test is assinge 'avalue'
And thus, without the actual $test assignment:
echo "$test $foo";
will result in:
"avalue test"
HTH,
Curt
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