Thanks for the quick reply, I wasn't aware that passing a variable for the
object would work.
New code:
class testClass {
function testFunction($foo) {
return $foo=="TEST";
}
}
$testObj = new testClass;
$testFunc = "testFunction";
echo $testObj->$testFunc("TEST");
-----Original Message-----
From: Pahlevanzadeh Mohsen [mailto:[EMAIL PROTECTED]
Sent: Friday, August 27, 2004 7:24 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] Dynamic Function with return?
1 way is here.You can use object & OOP.
--- bskolb <[EMAIL PROTECTED]> wrote:
> Sample Code:
>
> //================================
> <?PHP // version 4.3.6
> function testFunction($foo) {
> return $foo=="TEST";
> }
>
> function wrapper($foofunc, $foovar) {
> return eval("return $foofunc($foovar);"); }
>
> echo wrapper("testFunction", "TEST");
> ?>
> //================================
>
> This code works. It calls the function and receives the appropriate
> return value.
>
> But, is there a better way of doing this?
> It seems a bit round-a-bout.
>
>
> Thanks!
>
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Network administrator & programmer
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