> Dre wrote: > > line 8 is <?php > > > > just that .. and the code before it is the following > > > > //================================================== > > <html> > > <head> > > <title>Untitled Document</title> > > <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> > > </head> > > > > <body> > > //================================================== > > > > That is the output I mentioned. > > And output either html OR image, you cannot output both. Try yourself, > open a image file (gif, jpg...) in a text editor and put html code in > it, then save it. Obviosly, you'll get broken image file. >
As others have mentioned, you cannot output *anything* at all before modifying headers. If your script outputs even a space, headers are sent. Headers can only ever be sent one time per request. The solution: make a separate request for the image. To get around this problem put your image fetching code into a separate script and call it with an image tag. Ideally, you would have saved the image sizes in a separate column so you might select only the id (or name of the image) and the size in your main script and then call the second image fetching script like so: <img src="image.php?img_id=$id" width="$width" height="$height" border="0" /> The $id, $width, and $height would have come from your db. Save the actual fetching of the image itself for image.php. Good luck and have fun! Jim Grill > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
