the problem is that when i do a echo shows me:
"SELECT * FROM oposicions WHERE id = ''"
----- Original Message -----
From: "raditha dissanayake" <[EMAIL PROTECTED]>
To: "Jorge" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Sunday, September 05, 2004 6:01 PM
Subject: Re: Fw: [PHP] ERROR IN THIS CODE
> Is this part of a guessing game?
> do you want us to guess the error message you are seeing?
>
> Jorge wrote:
>
>>
>> include('include/conexion.php');
>> include('include/conf.php');
>>
>> $sql = "SELECT * FROM
>> oposicions WHERE id = '$id'";----------------> I think that the
>> problem is here.
>>
>>
>> $result = mysql_query($sql,
>> $link);
>>
>> while(
>> ($row=mysql_fetch_object($result)) ) {
>> $nome = $row->nome;
>>
>>
>> In my database exist the table oposicions with a field called id.My
>> php version es 4.3.38 and of mysql is 3.23.58
>>
>> thank you in advance
>>
>
>
> --
> Raditha Dissanayake.
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