Hi guys,
I have this code Javascript code:
if (document.images) {
img1on = new Image(); img1on.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_home_on; ?>";
img2on = new Image(); img2on.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_programdetails_on; ?>";
img3on = new Image(); img3on.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_products_on; ?>";
img4on = new Image(); img4on.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_featuredproducts_on; ?>";
img5on = new Image(); img5on.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_faq_on; ?>";
img6on = new Image(); img6on.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_contact_on; ?>";
img1off = new Image(); img1off.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_home_off; ?>";
img2off = new Image(); img2off.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_programdetails_off; ?>";
img3off = new Image(); img3off.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_products_off; ?>";
img4off = new Image(); img4off.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_featuredproducts_off; ?>";
img5off = new Image(); img5off.src = "<?php echo $base_url;
?>Graphics/<?php echo $img_faq_off; ?>";
img6off = new Image(); img6off.src = "<?php echo
"{$base_url}Graphics/{$img_contact_off}"; ?>";
}
When I include it in the main page it works without any problems. When I
link it as an external file it doesn't work.
As a side note, the following code example works in an external JS file:
img1off = new Image(); img1off.src = "<?php echo $base_url;
?>Graphics/home_off.gif";
Anyone know why the external file with two variables is not working but
it does work with one variable?
Thanks! I appreciate the help!
Regards,
Aaron
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
