RE: [PHP] Question in posting form-data

[Yao, Minghua]

Thanks. I changed 

fputs($fp, "$value\n");

to

fputs($fp, "$name=$value\n");


But I still got the same message.

-Minghua

-----Original Message-----
From: Erwin Kerk [mailto:[EMAIL PROTECTED]
Sent: Thu 12/16/2004 6:30 AM
To: Yao, Minghua
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Question in posting form-data
 
Yao, Minghua wrote:
> Hi, all,
> 
> I am testing how to post form-data to a host using the following code 
> (test.php):
> 
> <?php
>         function PostToHost($host, $path, $name, $value) {  // Test of 
> posting form-data
>               $fp = fsockopen($host,80);              
> 
>               fputs($fp, "POST $path HTTP/1.1\n");
>               fputs($fp, "Host: $host\n");
>               fputs($fp, "Content-Type: multipart/form-data\n");
>               fputs($fp, "content-disposition: form-data; name=$name\n");
>               fputs($fp, "Connection: close\n\n");
> 
>               fputs($fp, "$value\n");
> 
>               $res = "";
>               while(!feof($fp)) {
>                       $res .= fgets($fp, 128);
>               }
>               
>               fclose($fp);
> 
>               return $res;
>       }

Check your function carefully. Where are you using the $name of the value?

Nowhere! Therefore the receiving script cannot identify the value as x.

Try: fputs($fp, "$name=$value\n");



Erwin