print "<table>\n"; print "<tr>\n";
$counter = 0;
while ($result = mysql_fetch_array($pointer)) {
$counter++;
if ($counter % 4 === 0) {
print "<td>".$result[1]."</td>\n";
print "</tr>\n";
print "<tr>\n";
} else {
print "<td>".$result[1]."</td>\n";
}
}// add blank cells if number of cell on last row isn'4 four.
for ($i = 0; $i < $counter % 4; $i++) {
print "<td> </td>\n";
}print "</tr>\n"; print "</table>\n";
---------------------------------
Larry L wrote:
I'm sure this is easy and I'll feel silly when I see how it's done, but, my mnd is a blank,
this structure prints out a table with a new row for each item
<table > <? While ( $results = mysql_fetch_array($pointer)) { print "<tr><td ><$results[1] </td></tr>" ; } ?> </table>
what I want to do is print out a table 4 columns wide and however many rows high needed to run through the data
HOW do I loop through the array and get <td>data</td> printed 4 times then a new row started and then 4 more <td> cells printed, etc
thank you in advance
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