Re: [PHP] convert hidden form to get url

[Matt M.]

> Sorry for not been clear. The snippet of html is code I am getting
> dynamically using curl from another website. I want to then convert that
> html code into a url like
> http://www.somewebsite.co.uk/Availability?NUM_OF_ADTS=1&CABIN=E&B1_DAY=27.


you need something to parse the html, I found this: 
http://php-html.sourceforge.net/

and here is a quick script to try:

  include ("htmlparser.inc");

  $htmlText = '<form
action="http://www.somewebsite.co.uk/Availability.cgi"; method="POST"
name="flightsForm" id="flightsForm">
<input type="hidden" name="NUM_OF_ADTS" value="1"/>
<input type="hidden" name="CABIN" value="E"/>
<input type="hidden" name="B1_DAY" value="27"/>
</form>';

  $parser = new HtmlParser ($htmlText);
  while ($parser->parse()) {
     
      // Data you can use here:
      //
      // $parser->iNodeType
      // $parser->iNodeName
      // $parser->iNodeValue
      // $parser->iNodeAttributes     

      if ($parser->iNodeType == NODE_TYPE_ELEMENT) {
        $tmp = $parser->iNodeAttributes;
        if($parser->iNodeName == 'form') {
                $url = $tmp['action'];          
        } elseif($parser->iNodeName == 'input') {
                $qs[$tmp['name']] = $tmp['value'];
        }
      }
  }

$tmp = array();
foreach($qs as $key => $value) {
        print "$key => $value <br />";
        $tmp[] = $key.'='.urlencode($value);
}

$url .= '?'.implode('&',$tmp);

print 'url='.$url;

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