nevermind...i figured it out. I will read up on sessions and test some things with what you posted and if i have anymore questions, i will post them. Thanks Jerry.

If anyone else has any other suggestions, please feel free to share them with me.

JHollis wrote:
Where do i need to start my session? Ive copied and pasted exactly what you have typed..and the form doesnt display unless i hard code the variable to "NO".

Jerry Kita wrote:

I do exactly the same thing on my website. I use PHP's Session handling to determine if a user is actually logged on.

You can see that I check a variable called $validlogon which I set to either YES or NO at the beginning of the script

<?php
if ($validlogon == "NO") {
print "<p class=\"hnavbar\">Salkehatchie Members Login Here:<br>\n";
print "<form action=\"Salkehatchie_LoginScript.php\" method=\"POST\">\n";
print "<p class=\"login\"><small>USER ID:</small><br>\n";
print "<input type=\"text\" name=\"userid\"><br><br>\n";
print "<small>PASSWORD:</small><br>\n";
print "<input type=\"password\" name=\"password\"><br><br>\n";
print "<input type=\"submit\" value=\"Enter\"></p>\n";
print "</form>\n";
                          }
?>

Near the beginning of my script I check for the existence of a valid session

<?php
if (isset($_SESSION[userid])) {
   $validlogon = "YES";
   } else {
   $validlogon = "NO";
   }
?>

Setting the $validlogon variable allows me to do a number of useful things. For example, there are certain parts of the webpage that I reveal to logged in users. Checking $validlogon allows me to decide dynamically what to render to the browser. In the following I display
a message showing the user as being logged in and give them a link that
logs them out.


if ($validlogon == "YES") {
print "<table style=\"width: 100%\";>\n";
print "<tbody>\n";
print "<tr>\n";
print "<td width=\"50%\"><p class=\"login\"><small><b>YOU ARE LOGGED IN AS: $_SESSION[userid]</b></small></p></td>\n";
print "<td width=\"50%\"><p class=\"login\"><small><b>CLICK <a href=\"LogoutScript.php\"> here</a> TO LOGOUT</b></small></p></td>\n";
print "</tr>\n";
print "</table>\n";
}


Hope this is helpful

Jerry Kita

JHollis wrote:

I had this code working the way i wanted it to (as far as correct username and password allowing successful login)...but what i want to happen now is when a user successfully logs it it will make the login form disappear and just say successfully logged in or welcome user and a link below it so they can log off and make the form re-appear. Below is the code that i have where i tried to get it to disappear on successful login, but it stays disappeared all the time. Can someone please point out what im doing wrong. I have tried everything i can think of...and nothing works. Im a PHP newbie...so im sure some of you might get a laugh out of this...if it is real easy.

<---snippet


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
<html>
<head>
<link href="style.css" rel="stylesheet" type="text/css" />
</head>
<body>
<div id="container">
<div id="top">
<h1>header</h1>


</div>
<div id="leftnav">
<p>

    <?php

$username=$_POST['username'];
$password=$_POST['password'];
$db="user";
$server="localhost";
$db_username="root";
$db_password="*******";
$connect = mysql_connect($server,$db_username,$db_password);
if (!$connect) {
die ("could not connect to database");
}
$select = mysql_select_db($db,$connect);
if (!$select) {
die ("could not select database $db");
}
/*username='$username'";*/
$sql = "SELECT * FROM passwords, user_info where id=PID and username='$username'";
$result = mysql_query($sql);
/*$num_rows = mysql_num_rows($result);*/
while ($user = mysql_fetch_array($result))
{
$id = $user['id'];
$username2 = $user['username'];
$password2 = $user['password'];
$firstname = $user['firstname'];
$email = $user['email_address'];
IF ($username=="$username2" && $password=="$password2")
{
echo("\"Welcome, <b>$firstname</b>\"");?><br><?
echo ("\"Your email address is <b>$email<b>\"");?></td><tr>
<a href="<?$_SERVER['PHP_SELF']?>?username=""&?password=""">Logoff</a><?
break;
}
else
{
?>
<FORM action="<?$_SERVER['PHP_SELF']?>" method="post">
<INPUT type="hidden" name="id">
<table>
<td><b>*</b>Username:</td> <td><INPUT class="input" size="8" type="text" name="username" value="<?echo $username?>"></td><tr>
<td><b>*</b>Password:</td> <td><INPUT class="input" size="8" type="password" name="password"></td><tr>
<td class="xsmall"><b>* Case Sensitive</b></td>
<td><INPUT type="submit" value="Login"></td><tr>
<td>&nbsp </td>
</table>
</FORM>
<?
break;
}
} //IF ($username != $username2 || $password != $password2) {//


          ?><br>
    <?
    if  ($username == "" && $password == "") {
        echo ("Please type in a Username and Password");}

    if  ($username != "" && $password == "") {
        echo ("Please type in a password");}

if ($username == "" && $password != "") {
echo ("Please type in a username and password");}
?>
</p>
</div>
<?if (($username2==$username && $password2==$password) && ($username2!="" || $password2!="")){?>
<div id="rightnav" class="box">
<p>
</p>
</div>
<?}?>
<div id="content">
<h2>Subheading</h2>
<p>
</p>
<p>
</p>
</div>
<div id="footer">
<p>
Today is
<?php
echo( date("F dS Y."));
?>
</p>
</div>
</div>
</body>
</html>
---->snippet





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