sounds like there's something up with the query, perhaps the wrong table
name.
as a debugging method I usually use the die() clause when performing a query
so I can ensure the query is correct.
try using this:
$qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC") or
die("could not run the query: " . mysql_error());
chances are there is not a "blog_entries" table or an "id" field in the
database you're connecting to.
hope that helps,
brian
on 1/6/05 12:50 PM, Wil Hitchman at [EMAIL PROTECTED] wrote:
> I get the following error
>
> Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
> resource in /home/wilmail/public_html/elblog.php on line 7
> &n=& //error ends here
>
> with the following bit of code
>
> $qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC");
>
> $nRows = mysql_num_rows($qResult);
> $rString ="&n=".$nRows;
>
> If I am just naming a variable how is the argument not valid?
>
> Thanks,
>
> Wil
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