"John Taylor-Johnston" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> I might be doing this backwards, but how do I extract the date from $week5
and display $week5 + 4 days. I would like to create a function so when I
pass
>
> echo displaydate($week5);
>
> it echos "February 14-18"
>
> $week0 = "2005-01-10";
> $week1 = "2005-01-17";
> $week2 = "2005-01-24";
> $week3 = "2005-01-31";
> $week4 = "2005-02-07";
> $week5 = "2005-02-14";
> $week6 = "2005-02-21";
> $week7 = "2005-02-28";
>
> `Doable´? Easy enough to learn how to do?
>
> John
Hi John,
// convert your data to a timestamp:
$firstDayTs = strtotime($week5);
// add 4 days
$lastDayTs = $firstDayTs + (4 * 86400);
echo date('F', $firstDayTs) . ' ' . date('m', $firstDayTs) . '-' . date('m',
$lastDayTs);
Not tested. Maybe there's an easier way to do this.
Regards, Torsten Roehr
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