[snip] I'm trying to replace a substr of the string that start from "Rated blahblah;" azt the end semicolon.
Example: safsagfasdfsdfdsfRated by 4 people;fafafaafafaf -> return safsagfasdfsdfdsffafafaafafaf $replacement =""; $pattern = "/Rated.+;/"; $found_str = preg_replace($pattern, $replacement, $found_str); Why this above, doesn't work? [/snip] What does it return? Try this ... $string = "safsagfasdfsdfdsfRated by 4 people;fafafaafafaf"; $replacement =""; $pattern = "/Rated.+;/"; $found_str = preg_replace($pattern, $replacement, $string); echo $found_str; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
