Not exactly clear what database you're using. In SQL Server the syntax is SELECT [options] FROM [table] WHERE [field] LIKE '%whatever value you're looking for%'
The % means any string of characters, so it doesn't have to be exact Best of luck Nate Tobik (412)661-5700 x206 VigilantMinds -----Original Message----- From: David Freedman [mailto:[EMAIL PROTECTED] Sent: Friday, February 25, 2005 3:28 PM To: php-general@lists.php.net Subject: [PHP] Difficulty with SQL LIKE clause When I use this query in PHP it works, and I get all things with the YEAR of 1977, as I expected. $query= "SELECT * FROM my_table WHERE Year LIKE 1977 "; But, when I use this query it does not work. $query= "SELECT * FROM my_table WHERE Year LIKE 197* "; I thought I should get the result of ALL things with the years in the 1970's (1970-1979). But the asterisk in the LIKE clause does not seem to work. I have tried various syntax's to try to get the 197* recognized but without any luck. Can the '*' be used? What am I doing wrong. David F. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
