Greetings Mr Mattias, I wish it was so simple. Because the dates that may need calculating can be before 1970.
THis function I have.. and it's semi-working, but I've noticed irregularities during the conversion. Thanks for your suggestion!! Yours, Kevin "Mattias Thorslund" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > M. Sokolewicz wrote: > > > well, you can simply use the unix timestamp, since the amount of days > > / seconds since 0 AD/BC will be a constant (it won't change, trust > > me), you can simply add it to that, and add a wrapper function to > > php's time(). You'll be working with VERY big numbers in that case, so > > you can also do it the other way around; store the amount of DAYS > > since 0 AD/BC till Jan 1st 1970, add time()/86400, and you'll have the > > amount of days since 0 AD/BC in an integer (or float, depending on how > > many days that really are). > > > > You'll just need to find that constant somewhere :) > > > > Can't be too hard to calculate it: > > 1970 * 365 + 1 day for each leap year. Note the rules for leap year, of > course. > > /Mattias > > -- > More views at http://www.thorslund.us -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
