not for the same array it can't, the pointer in the first foreach is moved
by the second one
try:
$array = array("a", "b", "c");
foreach($array as $val1)
{ foreach($array as $val2) echo "$val1:$val2<br>";
}
it gives
a:a
a:b
a:c
then stops, the manual says that the foreach creates it's own pointer which
it obviously doesn't.
I can't remember what I was trying to do when I found this, it might have
been writing a recursive function
Tim Ward
Senior Systems Engineer
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> -----Original Message-----
> From: Maxim Derkachev [mailto:[EMAIL PROTECTED]]
> Sent: 12 April 2001 16:23
> To: Tim Ward
> Cc: [EMAIL PROTECTED]
> Subject: Re[2]: [PHP] foreach vs. while(list() = each())
>
>
> Hello Tim,
>
> Thursday, April 12, 2001, 1:43:53 PM, you wrote:
>
> TW> you can't nest foreach as you should be able to. Ecah
> foreach is supposed to
> TW> have it's own pointer in the array, but it doesn't ...
> this is a known bug.
>
> What do you mean? Foreach() can be nested, and it works perfect.
>
> <?php
> $a = array (array (1, 2, 3), array(4,5,6), array(7,8,9));
> foreach ($a as $k => $first) {
> print "$k:\n";
> foreach ($first as $second) {
> print "\t$second\n";
> }
> }
> ?>
>
> output:
> 0:
> 1
> 2
> 3
> 1:
> 4
> 5
> 6
> 2:
> 7
> 8
> 9
>
>
>
>
> --
> Best regards,
> Maxim Derkachev mailto:[EMAIL PROTECTED]
> Symbol-Plus Publishing Ltd.
> phone: +7 (812) 324-53-53
> http://www.Books.Ru -- All Books of Russia
>
>
>
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