Prathaban Mookiah wrote:
Mark,
Back to basics budy!!
25 if ($myrow = mysql_fetch_array($result)); {
should be
25 if ($myrow = mysql_fetch_array($result)) {
Note that extra semicolon?
Prathap
---------- Original Message ----------- From: Mark Sargent <[EMAIL PROTECTED]> To: php-general@lists.php.net Sent: Tue, 26 Apr 2005 16:01:24 +0900 Subject: [PHP] Parse error: parse error, unexpected T_ELSE
Hi All,
again, I'm following an example from webmonkey,
http://webmonkey.wired.com/webmonkey/99/21/index3a_page2.html?tw=programming
and I'm changing only what's relevant to me. I haven't altered the code basics, though. But I get the error regarding "else". I don't see what it is. Anyone..? Cheers.
Mark Sargent.
*Parse error*: parse error, unexpected T_ELSE in */var/www/html/phpmysqltable.php* on line *41*
25 if ($myrow = mysql_fetch_array($result)); {
26
27 echo "<table border=1>\n";
28
29 echo "<tr><td>Product Name</td><td>Product Model Number</td><td>Product
30 Serial Number</td></tr>\n";
31
32 do {
33
34 printf("<tr><td>%s</td><td>%s</td><td>%s</td></tr>\n", $myrow[product_name], $myrow[product_model_number],
35 $myrow[product_serial_number]);
36
37 } while ($myrow = mysql_fetch_array($result));
38
39 echo "</table>\n";
40
41 } else {
42
43 echo "Sorry, no data is available for that request";
44
45 }
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------- End of Original Message -------
Hi All,
yep, basics are good, hence my following the tut at webmonkey(so I can learn the basics), and I obviously missed that little error. Cheers.
P.S. Some people are mailig me direct. That's great, but, I'd prefer you reply in here, so all can see/comment. Cheers, again.
Mark Sargent.
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