Robert Cummings wrote:
...


There's a difference between a reference to a reference and a copy of a
reference *hehehe*.

Cheers,
Rob.

Dear diary: jackpot!

Now that makes sense. And am I correctly filling in the blanks when I guess that $foo3 = $aObj is merely copying the reference instead of referencing the reference? I probably could have written that more clearly, but I think you get what I'm saying.

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