Hi Jasper and thanks for the quick reply.
something tells me it's not a straightforward SQL query that I have to use
here but a logic using PHP and SQL.
Mario
----- Original Message -----
From: "Jasper Bryant-Greene" <[EMAIL PROTECTED]>
To: <php-general@lists.php.net>
Sent: Wednesday, June 29, 2005 4:28 AM
Subject: [PHP] Re: date problem
Firstly, this shouldn't be in the PHP list, as you're asking for help
with SQL.
Mario netMines wrote:
carrental_from (datetime field)
carrental_to (datetime field)
carrental_price (datetime field) [rates are per hour]
carrental_price shouldn't be a datetime field, as it isn't a datetime
value.
The values I have are like:
0000-00-00 00:00:00,0000-00-00 07:00:00,10 (all year around 00:00-07:00)
0000-00-00 07:00:00,0000-00-00 00:00:00,20 (all year around 07:00-00:00)
2005-12-22 07:00:00,2006-01-02 00:00:00,15 (christmas period 00:00-07:00)
2005-12-22 00:00:00,2006-01-02 07:00:00,25 (christmas period 07:00-00:00)
The user selects dates ($from - $to) to rent a car and he gets the price
accordingly.
I can do a (($to-$from)/60/60) and get the total number of hours but
depending on the date and time you get a different result. Can anyone
help with the SQL?
Read up on the MySQL DATEDIFF() function, if you are using MySQL. Other
DBMSs should have an equiv. function.
Jasper
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