It might also be a factor, but the variable containing the table name is
$table (not $table1 as coded in the query string).

Warren Vail
[EMAIL PROTECTED]

> -----Original Message-----
> From: Philip Hallstrom [mailto:[EMAIL PROTECTED] 
> Sent: Thursday, September 08, 2005 6:41 PM
> To: Iggep
> Cc: php-general@lists.php.net
> Subject: Re: [PHP] Inserting records question
> 
> 
> > Still learning, so sorry if this sounds really simply 
> noobish.  But as 
> > I understand things currently this should work.  But doesn't.  I've 
> > been looking over tutorials but just don't see whatever the problem 
> > is.
> >
> > I created a simple table with the following fields (in order) tc_id 
> > (auto nmbr) lname
> > fname
> > machine_name
> > email_addr
> > problem
> > date_time_submitted (timestamp)
> >
> > And I'm trying to run this insert from form input.
> >
> >             $username="somename";
> >             $password="somepass";
> >             $database="somedb";
> >             $table="sometable";
> >             mysql_connect(localhost,$username,$password);
> >             @mysql_select_db("$database") or die("Unable to 
> Connect to DB");
> >             $tc_query = "INSERT INTO $tablel VALUES(NULL, 
> $lname, $fname, 
> > $machine_name, $email_addr, $problem, NULL)";
> >             $result = mysql_query($tc_query);
> >             mysql_close();
> >
> > So what exactly do I seem to be missing here?
> 
> A lot of single quotes... around the parameters you are inserting...
> 
> add in a print($tc_query) and see what that looks like... run that 
> directly in mysql and it will give you more details on the error.
> 
> Or, make it look like this:
> 
> $tc_query = "INSERT INTO $tablel VALUES(NULL, '$lname', '$fname', 
> '$machine_name', '$email_addr', '$problem', NULL)";
> 
> I'd also suggest you read this page:
> 
http://www.php.net/mysql_escape_string

good luck!

-p

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