On 18/04/06, Ross <[EMAIL PROTECTED]> wrote:
>
> $query1= "select * from $table_name WHERE sname LIKE '$search_string%' ";
>
> if ($area="a") {
> $query1 .=" AND area='a'";
> }
> else {
> $query1 .="AND area='$area'";
> }
Firstly, you're assigning "a" to area rather than testing whether
$area is "a". You need a "==" operator, not a "=".
Secondly, even if you were testing $area properly, you're doing the
same thing in both halves of the if-statement. Which isn't very
useful.
Really, you only need the "AND area='?'" part if $area is not equal to "a":
if ($area != "a") {
$query1 .= " AND area='$area'";
}
-robin
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